Agas mixture contains 1.20 g n2 and 0.77 g o2 in a 1.65-l container at 15 ∘c. part a calculate the mole fraction of n2. express your answer using two significant figures. x1 x 1 = nothing request answer part b calculate the mole fraction of o2. express your answer using two significant figures. x2 x 2 = nothing request answer part c calculate the partial pressure of n2. express your answer using two significant figures. p1 p 1 = nothing atm request answer part d calculate the partial pressure of o2. express your answer using two significant figures. p2 p 2 = nothing atm request answer provide feedback

Explanation:

Moles of nitrogen gas =

Moles of oxygen gas =

Mole fraction of nitrogen gas=

Mole fraction of oxygen gas=

Total  umber of moles in container :

n == 0.0428 mol + 0.0240 mol = 0.0668 mol

Volume of the container = V = 1.65 L

Temperature of the container = T = 15°C = 288.15 K

Total pressure in the container = P

Using an ideal gas equation:

P = 0.9577 atm

Partial pressure of nitrogen gas =

Partial pressure of nitrogen gas =

Partial pressure of nitrogen gas and oxygen gas can be calculated by using Dalton's law of partial pressure:

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

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