A6.10 m nacl can be made by adding [x]g of nacl to a container and making the volume of water up to the 1.00 l line

356.484 g.

Explanation:

M = (no. of moles of NaCl)/(volume of the solution (L))

M = 6.10 M, volume of the solution = 1.0 L.

∴ No. of moles of NaCl = (M)(volume of the solution (L)) = (6.10 M)(1.0 L) = 6.10 mol.

∵ no. of moles of NaCl = (mass of NaCl)/(molar mass of NaCl)

∴ Mass of NaCl = (no. of moles of NaCl)(molar mass of NaCl) = (6.10 mol)(58.44 g/mol) = 356.484 g.

NaCl mass : 356.85 grams

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc

Mole

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³

Mole can also be sought if the amount of substance mass and its molar mass is known

known

M NaCl = 6.10 M

Volume = 1.00 L

asked

NaCl mass

solution

molar mass of NaCl: 23 + 35.5 = 58.5 g / mol

mole NaCl = gram / mass

mole NaCl = molarity x volume

mol of NaCl = 6.1 x 1

mole of NaCl = 6.1

NaCl mass = molar mass x mol

mass of NaCl = 58.5 x 6.1

mass of NaCl = 356.85 grams

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Keywords: mole, NaCl, volume, molarity