How many liters of water vapor can be produced if 108 grams of methane gas (ch4) are combusted at 312 k and 0.98 atm? show all work. pls ! will mark as brainliest

Approximately 352 liters of water vapor will be produced.

Assumption: the water vapor here behaves like an ideal gas.

Explanation:

Relative atomic mass data from a modern periodic table:

Burning methane in excess oxygen will produce carbon dioxide and water. The balanced equation will be

.

Hint: start by assign "1" to methane while balancing this equation.

How many moles of molecules in 108 gram of methane?

Molar mass of methane:

.

.

How many moles of water molecules will be produced?

Consider the ratio between the coefficient in front of water and that in front of methane in the equation:

.

.

Assume that water vapor here behaves like an ideal gas.

Ideal gas constant in liters and :

. (NIST.)

Make sure that the temperature here is in degrees Kelvins.

.

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