Ablock of aluminum is dropped into a graduated cylinder with an initial volume of water at 75ml and the volumes rises to 90ml. if the block has a mass of 40.5 g what is its density ?

=2.7 g/cm³

=2700 kg/m³

Explanation:

Density is a ratio of the mass of an object to its volume.

The volume of the named block of aluminium is calculated as follows:

90mL - 75mL= 15mL

15mL = 15 cm³

The mass = 40.5 g

Therefore ρ=m/v

=40.5g/15cm³

=2.7 g/cm³

=2700 kg/m³

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

16

explanation:

the marks go by 4s