Consider a situation in which 161 g of p4 are exposed to 176 g of o2. a.)what is the maximum amount of p2o5 that can theoretically be made from 161 g of p4 and excess oxygen? (i got 2.60 mol) b.)what is the maximum amount of p2o5 that can theoretically be made from 176 g of o2 and excess phosphorus? (i got 2.20 mol) c.)now, determine how many moles of p2o5 are produced from the given amounts of phosphorus and oxygen. (i got 2.20mol/ theoretical yield) is what i need d.)what is the percent yield if the actual yield from this reaction is 206g?

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.

i think its 100.

hope this !