Assigning oxidation numbersquick checkwhat are the oxidation numbers of the atoms in this reaction? check all that apply. mg(s) + 2hcl(aq) - mgcl2(aq) + h2(g

Mg = 0

H =+1

Cl= -1

Mg= +2

Cl=-1

H= 0

B,C,D,E

Explanation:

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points

explanation:

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally