If the pressure inside your ballon is 800mmhg ,and the gas is at body temperature,37 degree celsius , calculate the number of grams of air inside your ballon. the molar mass of air is 29g/mol . the volume is 3.7l

With all of the information given (pressure, volume, temperature, and the molar mass), we need a formula that relates this all together. The formula we need is the ideal gas law, PV=nRT. Since the pressure is defined in millimeters of mercury, we need the R value that correlates with this, which is 62.4; on top of this, we need the temperature in Kelvin - simply add 273.15 to convert from Celsius. With all of this information, simply plug-and-chug:

PV=nRT
(800)(3.7) = n(62.4)(37 + 273.15)
n = 0.1529 moles

Finally, the problem is asking the amount of air in grams. We have moles, so all we need to do is multiply that value by the molar mass.

0.1529 moles x 29 grams per mole =
4.435 grams of air

The balloon has 4.435 grams of air inside it.

Hope this helps!

Ithink that the answer is b