Chemistry, 29.06.2019 00:40 taylorbuck47

2c3h7oh(l) + 9o2(g) → 8h2o(g) + 6co2(g) the combustion of isopropanol, i. e. rubbing alcohol, releases 1,830 kj/mol. given that the molecular weight of isopropanol is 60.096 g/mol, calculate the enthalpy of combustion for 45.0g of isopropanol. a) 147 kj b) 1,370 kj c) 2,160 kj d) 4,950 kj

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2c3h7oh(l) + 9o2(g) → 8h2o(g) + 6co2(g) the combustion of isopropanol, i. e. rubbing alcohol, releas...