C3h8(g) + 2o2(g) → 4h2o(g) + 3co2(g) δhreaction=2,220 kj/mol calculate the enthalpy of combustion for 24.5g propane given the molecular weight of propane is 44.097 g/mol. a) 723 kj b) 1,010 kj c) 1,230 kj d) 2,390 kj

Option C) 1,230 kJ

Explanation:

According to the data, 1 mol of propane liberates 2,220 kJ of energy when it is combusted. If we have 24.5 g of propane, this mass is equal to 0,56 mol (of propane):

44.097 g of propane>1 mol

24.5 g of propanex= 0.56 mol

Then, the enthalpy of the described chemical reaction (propane´s combustion) is 2,220 kJ when 1 mol of propane is combusted, so:

1 mol propane>2,220 kJ of energy

0.56 mol propane (24.5 g)x= aproximately 1,24 kJ (which would be option C)