** worth 20 points + brainliest ** a pan containing 40 grams of water was allowed to cool from a temperature of 91.0 °c. if the amount of heat released is 1,300 joules, what is the approximate final temperature of the water? a. 74 °c b. 78 °c c. 81 °c d. 83 °c

Answer : The correct option is, (D)

Solution :

Formula used :

where,

Q = heat released = -1300 J

m = mass of water = 40 g

c = specific heat of water =      

= final temperature = ?

= initial temperature =

Now put all the given values in the above formula, we get the final temperature of water.

Therefore, the final temperature of the water is,

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.