Consider the following reaction: iron (s) + chlorine (g) à iron (iii) chloride a. write the balanced chemical equation. b. 25.0 g of iron reacts with excess chlorine gas. a. calculate the moles of iron reactant. b. calculate the moles of iron (iii) chloride. c. calculate the mass of iron (iii) chloride.

1) a. 2Fe(s) + 3Cl₂(g) → 2FeCl₃(s).

2) a. 0.4477 mol.

b. 0.4477 mol.

c. 72.61 g.

Explanation:

1) Consider the following reaction:  iron (s) + chlorine (g) à iron (III) chloride

a. Write the balanced chemical equation.

So, the balanced chemical equation is:

2Fe(s) + 3Cl₂(g) → 2FeCl₃(s).

It is clear that 2 mol of Fe(s) react with 3 mol of Cl₂(g) to produce 2 mol of FeCl₃(s).

2) 25.0 g of iron reacts with excess chlorine gas.  

a. Calculate the moles of iron reactant.

n = mass/molar mass = (25.0 g)/(55.845 g/mol) = 0.4477 mol.

b. Calculate the moles of iron (III) chloride.

Using cross multiplication:

2 mol of Fe produce → 2 mol of FeCl₃, from stichiometry.

∴ 0.4477 mol of Fe produce → 0.4477 mol of FeCl₃.

∴ The no. of moles of iron (III) chloride produced is 0.4477 mol.

c. Calculate the mass of iron (III) chloride.

mass of  iron (III) chloride = (no. of moles)*(molar mass) = (0.4477 mol)*(162.2 g/mol) = 72.61 g.

mechanics (greek   is that area of science concerned with the behaviour of physical bodies when subjected to forces or displacements, and the subsequent effects of the bodies on their environment. the scientific discipline has its origins in ancient greece with the writings of aristotle and archimedes[1][2][3] (see history of classical mechanics and timeline of classical mechanics). during the early modern period, scientists such as galileo, kepler, and newton laid the foundation for what is now known as classical mechanics. it is a branch of classical physics that deals with particles that are either at rest or are moving with velocities significantly less than the speed of light. it can also be defined as a branch of science which deals with the motion of and forces on objects. the field is yet less widely understood in terms of quantum theory.

explanation:

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.