The equation for enthalpy change (δh) at constant pressure (p) is δh = qp = δe + pδv, where qp is the heat lost or gained at constant pressure, δe is the change in the internal energy of the system, and δv is the change in volume (v2 − v1) of the system. a sample of gas is maintained at a constant pressure of 2.63 atm. after 617 j of thermal energy is applied to (and absorbed by) the gas, its internal energy has increased by 483 j. by how much has the volume of the gas changed? (include the sign of the value in your answer.)