During a synthesis reaction, 3.2 grams of magnesium reacted with 12.0 grams of oxygen. what is the maximum amount of magnesium oxide that can be produced during the reaction? mg + o2 → mgo 5.3 grams 6.5 grams 7.2 grams 9.5 grams

Answer : The correct option is, 5.3 grams

Explanation :

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react with 1 mole of

So, 0.133 moles of react with moles of

That means, in the given balanced reaction, is a limiting reagent because it limits the formation of products and is an excess reagent.

Now we have to calculate the moles of MgO.

As, 2 moles of react with 2 moles of

So, 0.133 moles of react with moles of

Now we have to calculate the mass of MgO.

Therefore, the mass maximum amount of magnesium oxide is, 5.3 grams

Answer : The maximum amount of magnesium oxide produced can be, 5.3 grams.

Solution : Given,

Mass of Mg = 3.2 g

Mass of = 12.0 g

Molar mass of Mg = 24 g/mole

Molar mass of = 32 g/mole

Molar mass of MgO = 40 g/mole

First we have to calculate the moles of Mg and .

Now we have to calculate the limiting and excess reagent.

Synthesis reaction : It is defined as the reaction in which the two smaller molecule combined to give one larger molecule.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 mole of react with 1 mole of

So, 0.133 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 2 mole of react to give 2 mole of

So, 0.133 moles of react to give 0.133 moles of

Now we have to calculate the mass of

Therefore, the maximum amount of magnesium oxide produced can be 5.3 grams.

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