At what temperature (in c) will a sample of gas occupy 91.3 l if it occupies 45.0 l at 70.0°c? assume constant pressure.)

The temperature at which the sample of gas occupy 91.3 L is 422.9 °C

From the question given above, the following data were obtained:

Initial volume (V₁) = 45 L

Initial temperature (T₁) = 70 °C = 70 + 273 = 343 K

Final volume (V₂) = 91.3 L

Pressure = constant

The final temperature of gas can be obtained by using the Charles' law equation as illustrated below:

Therefore, the temperature at which the sample of gas occupy 91.3 L is 422.9 °C

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Solution is here,

for initial case,

temperature(T1)=70°C=70+ 273=343K

vloume( V1) =45 L

for final case,

temperature( T2)=?

volume(V2)= 91.3 L

at constant pressure,

V1/V2 = T1/T2

or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

a. hope i'm right

explanation: