What is the volume in liters of 0.500 mol of c3h8 gas at stp

11.21 L.

Explanation:

where, P is the pressure of the gas in atm (P = 1.0 atm, Standard P).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 0.5 mol).

R  is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 273 K, Standard T).

∴ V = nRT/P = (0.5 mol)(0.0821 L.atm/mol.K)(273 K)/(1.0 atm) = 11.21 L.