The reaction of sodium peroxide and water produces sodium hydroxide and oxygen gas. the following balanced chemical equation represents the reaction.

2 na^2o^2(s) + 2 h^2o(l) → 4 naoh(s) + o2(g)

how many moles of sodium hydroxide are produced when 17.2 mol sodium peroxide reacts with water?

34.4 mol.

Explanation:

2 Na₂O₂(s) + 2 H₂O(l) → 4 NaOH(s) + O₂(g),

It is clear that 2 moles of Na₂O₂ react with 2 moles of H₂O to produce 4 moles of NaOH and 1 mole of O₂.

Using cross multiplication:

2 moles of Na₂O₂ produce → 4 mole of NaOH.

17.2 moles of Na₂O₂ produce → ??? mole of NaOH.

∴ The no. of moles of NaOH produced = (4 mole)(17.2 mole)/(2 mole) =  34.4 mol.

answer: lol

explanation:

lol

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6