How many grams of magnesium chloride are in 1.33 mol of mgcl2?

126.63 g.

Explanation:

Knowing that the no. of moles can be calculated using the relation:

no. of moles (n) = mass/molar mass

no. of moles MgCl₂= 1.33 mol & molar mass of MgCl₂ = 95.211 g/mol.

∴ mass = no. of moles * molar mass = (1.33 mol)*(95.211 g/mol) = 126.63 g.

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

The correct answer is "hydrogen".