What volume in ml of a 0.763 m solution of bai2 would be required if you wanted 0.0131 moles of solute? ml (picture attached)

The right answer is V = 17.2 mL

Explanation:

No. of moles = C * V

where,

C is the concentration in morality and

V is the volume in liter

so you can calculate the volume using:

V = (No. of moles / C) = (0.0131 mol / 0.763 mol/L)

V = 0.0172 L

 V = 0.0172 L * (1000 mL / 1 L)

  V = 17.2 mL

So, the right answer is V = 17.2 mL

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