A49.2 g sample of solid iron was heated from 16.2c to 58.9c. what ws the energy change? solve for q(heat energy).iron has a specific heat value of .4494

944.12 J

Explanation:

To solve for the energy change we use the equation Q=mc(Delta)t

Let's identify the variables we have:

m (mass) = 49.2 g

c (specific heat) = .4494

delta t (change in temp.) = final - initial = 58.9-16.2 = 42.7 degrees Celsius

Q= (49.2)(.4494)(42.7)

  = 944.12 J

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