Fifteen points! nothing like chemistry quizzes in the > o<

match the acids and bases to their correct type.

h²co³ a. monoprotic acid
hci b. diprotic acid
nh₄oh c. triprotic acid
h₃po₄ d. monoprotic base
ba(oh)₂ e. diprotic base

Explanation:

HA(aq)+H2O(l)⟺H3O+(aq)+A−(aq)(1)

you need to solve for the Ka value. To do that you use

Ka=[H3O+][A−][HA](2)

Another necessary value is the pKa value, and that is obtained through pKa=−logKa

The procedure is very similar for weak bases. The general equation of a weak base is

BOH⟺B++OH−(3)

Solving for the Kbvalue is the same as the Ka value. You use the formula  

Kb=[B+][OH−][BOH](4)

The pKb value is found through pKb=−logKb  

The Kw value is found withKw=[H3O+][OH−].  

Kw=1.0×10−14(5)

6.4 cm (max) - 25 cm (min)

56 moles of   lieter in chemistry