Nitrogen in a 29 l container at a pressure of 398 mm hg and 293 k is transferred to a container with a pressure of 307 mm hg. what is the new temperature if the volume changes to 156 l?

70.61°c=T₂

Explanation:

This question is on Combined Gas Laws

The volume of a gas is directly proportional to the absolute temperature and inversely proportional to the pressure.

P₁V₁T₁=P₂V₂T₂

where

P₁=Initial pressure, P₂=final pressure

V₁=Initial volume,V₂=final volume

T₁=Initial temperature in Kevin, T₂=final temperature in Kelvin

Given

P₁=398mm Hg,  V₁=29 L  and T₁=293 K

P₂=307 mm Hg, V₂=156 L  and T₂=?

Solution

P₁V₁T₁=P₂V₂T₂

Substitute values

398×29×293=307×156×T₂

3381806=47892T₂

3381806/47892=T₂

70.61°c=T₂

70.61+273=343.61 K