Element y is composed of three isotopes; y-20 is 15.00%, y-22 is 50.00%, and y-24 is 35.00%. what is the element y’s relative atomic mass

We take in account the following formula tot determine the relative atomic mass:

Relative atomic mass = atomic mass of isotope (1) × abundance of isotope (1) +

atomic mass of isotope (2) × abundance of isotope (2) + ... and so on

For element Y we have:

Relative atomic mass of Y = 20 × 0.15 + 22 × 0.5 + 24 × 0.35 = 22.4

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm