Asample of oxygen occupies 47.2 liters under a pressure of 1240 torr at 298k. what volume would it occupy at 303k if the pressure were decreased to 730 torr

81.5 L

Explanation:

We can use the combined gas law equation that gives the relationship among pressure, temperature and volume of gases for a fixed amount of gas.

P1V1 / T1 = P2V2 / T2

where P1 - pressure, V1 - volume and T1 - temperature at the first instance

P2 - pressure, V2 - volume and T2 - temperature at the second instance

substituting the values in the equation

1240 Torr x 47.2 L / 298 K = 730 Torr x V2 / 303 K

V2 = 81.5 L

the new volume the gas would occupy when the conditions have changed is 81.5 L

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a