When the pressure that a gas exerts on a sealed container changes from 811 mm hg to 415 mm hg, the temperature changes from 33.0°c to _ °c?

-116.42°C

Explanation:

According to pressure law which states that the pressure of a fixed mass of a gas is directly proportional to its absolute temperature at constant volume.

Therefore;

P1/T1 = P2/T2

P1 = 811 mmHg

P2 = 415 mmHg

T1 = 33°C + 273°C = 306 K

Therefore;

T2 = P2T1/P1

    = (415 × 306)/ 811

    = 156.58 K

Therefore; temperature = 156.58 - 273 = -116.42°C

answerapplication program;

answerca air mass;