Carbon disulfide burns with oxygen to form carbon dioxide and sulfur dioxide in the following manner: cs2 + 3o2 → co2 + 2so2

what is the volume of sulfur dioxide (so2 gas), formed when 2 moles of carbon disulfide (cs2) are burned? the reaction is taking place at stp.

5.6 l
22.4 l
89.6 l
44.8 l

89.6 L.

Explanation:

CS₂ + 3O₂ → CO₂ + 2SO₂.

Using cross multiplication:

1.0 mole of CS₂ produces → 2.0 moles of SO₂.

2.0 mole of CS₂ produces → ??? moles of SO₂.

∴ The no. of moles of SO₂ produced = (2.0 mol)(2.0 mol)/(1.0 mol) = 4.0 mol.

∴ 4.0 moles of SO₂ occupy = (4.0)(22.4 L) = 89.6 L.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml