How many protons and electrons are present in pb2+

82 PROTONS 80 ELECTRONS

Explanation:

Determine the number of protons, neutrons, and electrons in a 210Pb2+ ion. The atomic number of lead is 82, which means this ion contains 82 protons. Since it has a charge of +2 , this ion must contain 80 electrons.

The number of protons of the Pb is 82.

The number of electrons of the Pb²⁺ is 80.

Explanation:

Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z.  

The atomic number is used to classify the elements within the periodic table of the elements. In it, you can read in the upper left.  In this case, the lead Pb has an atomic number of 82. This indicates that the number of protons of the Pb²⁺ is 82.

In every electrically neutral atom the number of protons in the nucleus is equal to the number of electrons in their orbitals. But in this case it is a cation, that is, it is a positively charged ion. A cation is formed when electrons are lost (which have a negative charge), thus acquiring the positive charge ion. In this case then, Pb²⁺ indicates that the cation has a +2 charge. So this means that 2 electrons have been lost.  So, if it were electrically neutral, the lead Pb would have 82 electrons, but with the loss of two of its electrons, the number of electrons of the Pb²⁺ is 80.

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