Chemistry, 20.11.2019 22:31 kromaug1517

How many milliliters of 0.100 m naoh are required to neutralize the following solutions?

a.) 10.0 ml of 0.0500 m hcl
b.) 25.0 ml of 0.126 m hno3
c.) 50.0 ml of 0.215 m h2so4

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Answer from: nemorinavory3832

Answers:

a.) 10.0 mL of 0.0500 M HCl: 5.00 mlb.) 25.0 mL of 0.126 M HNO₃: 31.5 mlc.) 50.0 mL of 0.215 M H₂SO4: 215. ml

Explanation:

All the reactions are the neutralization of strong acids with the same strong base.

At the neutralization point you have:

number of equivalents of the base = number of equivalent of the acid

And the number of equivalents (#EQ) may be calculated using the normality (N) concentration and the volume (V)

# EQ = N × V

Then, at the neutralization point:

# EQ acid = N acid × V acid# EQ base = N base × V base# EQ acid = # EQ baseN acid × V acid = N base × V base

Also, you can use the formula that relates normality with molarity

N = M × number of hydrogen or hydroxide ions

a.) 10.0 mL of 0.0500 M HCl

The number of hydrogen ions for HCl is 1 and the number of hydroxide ions for NaOH is 1.10.0 ml × 0.0500 M × 1 = V base × 0.100 M × 1

⇒ V base = 10.0 ml ×0.0500 M / 0.100 M = 5.00 ml

b.) 25.0 mL of 0.126 M HNO₃

The number of hydrogen ions for HNO₃ is 1 and the number of hydroxide ions for NaOH is 1.25.0 ml × 0.126 M × 1 = V base × 0.100 M × 1

⇒ V base = 25.0 ml ×0.126 M / 0.100 M = 31.5 ml

c.) 50.0 mL of 0.215 M H₂SO4

The number of hydrogen ions for H₂SO4 is 2 and the number of hydroxide ions for NaOH is 1.50.0 ml × 0.215 M × 2 = V base × 0.100 M × 1

⇒ V base = 50.0 ml ×0.215 M × 2 / 0.100 M = 215. ml

Answer from: Quest

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

Answer from: Quest

i think it's letter a.

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How many milliliters of 0.100 m naoh are required to neutralize the following solutions?