Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to question 1 options:

Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to increase by 3.0 times.

Explanation:

So, for two different values of both P and V:

∴ P₁V₁ = P₂V₂.

∵ V₂ = 1/3V₁

∴ P₂ = P₁V₁/V₂ = P₁V₁/(1/3V₁) = 3P₁.

d is

c (diamond),

sio2 (quartz)