What is an important step to determine the number of grams of so3 that can be produced by reacting 6 moles of so2 with oxygen in the synthesis reaction below. 2 so2(g) + o2(g) —> 2 so3(g)

480.40 g.

Explanation:

2 SO₂(g) + O₂(g) → 2 SO₃(g),

it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.

∵ 2.0 moles of SO₂ produce → 2.0 moles of SO₃, from the stichiometry.

∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.

mass =  no. of moles x molar mass of SO₃ = (6.0 moles)(80.066 g/mol) = 480.396 g ≅ 480.40 g.

where is the following

explanation: