When a mercury-202 nucleus is bombarded with a neutron, a proton is ejected. what element is formed?

That will make a gold-202 nucleus.

Explanation

Refer to a periodic table. The atomic number of mercury Hg is 80.

Step One: Bombard the with a neutron . The neutron will add 1 to the mass number 202 of . However, the atomic number will stay the same.

New mass number: 202 + 1 = 203.Atomic number is still 80.

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Double check the equation:

Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.

Step Two: The nucleus loses a proton . Both the mass number 203 and the atomic number will decrease by 1.

New mass number: 203 - 1 = 202.New atomic number: 80 - 1 = 79.

Refer to a periodic table. What's the element with atomic number 79? Gold Au.

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Double check the equation:

Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.

A gold-202 nucleus is formed.

Sorry i dont understand the question can you rephase it?

Ametal with a large number of free flowing electrons most likely has good conductivity