A25.5 ml aliquot of hcl of unknown concentration was titrared with .113 m naoh. it took 51.2 ml of the base to reach the endpoint of the titration. the concentration (m) of the acid was ?

Answer;

0.227 M

Explanation;

Volume of HCl = 25.5 mL or 25.5 / 1000 => 0.0255 L

Molarity or concentration of NaOH  = 0.113 M

Volume of NaOH  = 51.2 mL / 1000 = 0.0512 L

Number of moles NaOH:

Moles = Molarity x Volume

            = 0.113 x  0.0512

            = 0.0057856 moles of NaOH

From the equation we can obtain the mole ratio:

HCl + NaOH = NaCl + H2O

1 mole HCl : 1 mole NaOH

Therefore;

Moles of  HCl : 0.0057856 moles NaOH

Hence; moles of HCl  =  0.0057856 x 1 / 1

                                    =  0.0057856 moles of HCl

Molarity of  HCl = moles of HCL / Volume of HCl

                         M =  0.0057856 / 0.0255

                              = 0.227 M

Following are the  advantages of the parametric equations: 1) they can be used to graph curves that are not functions, like the unit circle.2) the parameter can be used to represent the quantity that is  useful to  provide us with better information about the graph.3)  it is useful to convert between rectangular equations and parametric equations.with specific reference to chemistry,  parametric equations are employ for solving hydrogen and hydrogen-like ions, quantum mechanically. herein, cartesian coordinates are converted in spherical polar coordinates. the solution obtained, when plotted on spherical polar graph paper, provides visualization of atomic orbital such as s,p,d and f.