The half-life of cesium-137 is 30 years. suppose we have a 40 mg sample. exercise (a) find the mass that remains after t years. step 1 let y(t) be the mass (in mg) remaining after t years. then we know the following. y(t) = y(0)ekt = · ekt exercise (b) how much of the sample remains after 20 years? step 1 after 20 years we have the following. y(20) = 40 · 2 = mg (round your answer to two decimal places.)
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