If water with a mass of 0.755 absorbs 0.954j of heat, how much will its temperature increase?
a. 0.221
b. 0.302
c. 0.095
c. 0.564

B. 0.302.

Explanation:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by water (Q = 0.954 J).

m is the mass of water (m = 0.755 g).

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  ??? °C).

∴ ΔT = Q/m.c = (0.954 J)/(0.755 g)(4.186 J/g.°C) = 3.018 °C ≅ 3.02 °C.

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).