What is not the same as 0.953 kilograms

Here, I'll show you an EASY conversion acronym:Kangaroos, Hopping Down Mountains Drinking Chocolate Milk:That is KHDMDCM.Now, here's what they ACTUALLY stand for:Kilo, (kilometers, kilograms, etc.), Hecto, (hectograms, hectometers, etc.), Deca, (decameters, decagrams, etc.), M stands for THREE things, Meters, liters, and grams, Deci, (decimeters, decigrams, etc.), Centi, (centimeters, centigrams, etc.), and Milli, (millimeters, milligrams, etc.).Now, you look at the diagram I have provided below:You put 0.14 under Meters, liters, and grams, because it's 0.14 meters.Now, whenever you move RIGHT, you move the decimal RIGHT every time you move. If there is a WHOLE number, (like 14), you add a ZERO to the number, so when you would move 14 to the RIGHT, it would become 140. Now when you go LEFT, you move the decimal to the LEFT, and if there are ANY ZEROS, you would take them out.Now you might get a little confused when moving left;Look, EVERY NUMBER has a decimal, like the number 14 itself.14 has an imaginary decimal, which is 14.0. EVERY NUMBER HAS THAT. So, if you are moving LEFT, and you DON'T have any zeros, you would simply have 14 into 1.4.So, with that out of the way, let's start figuring out how many centimeters 0.14 is equivalent to.So we move to the RIGHT, because the centimeters is on the RIGHT, and now we move the decimal to the right.Now it would be 01.4, but it's the same as 1.4, so we'll just put 1.4 under deci.Now we have 1.4 DECIMETERS, but not quite yet centimeters.We must keep moving to the right.Once we move that decimal AGAIN, it is now 14. WOO HOO! WE FIGURED IT OUT!So 0.14m = 14 cm.You saw how we figured that out? You could use this technique on ANY conversion problem like this in the future! 
So now what would NOT be the same would be 9.54 hectograms.
Hope this helps ;)

Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.