Will give brainlist or whateve.

1. a note has a wavelength of 0.58399 m. if the speed of sound is 343.00 m/s, what pitch is this note?

2. a note has a wavelength of 0.69450 m. if the speed of sound is 343.00 m/s, what pitch is this note?

3. a note has a wavelength of 0.49108 m. if the speed of sound is 343.00 m/s, what pitch is this note?

4. an a note has a frequency of 440.00 hz. calculate its wavelength in meters.

5. an e note has a frequency of 659.26 hz. calculate its wavelength in meters.

6. a c note has a frequency of 523.25 hz. calculate its wavelength in meters.

7. a note has a wavelength of 0.43750 m. if the speed of sound is 343.00 m/s, what pitch is this note?

8. a note has a wavelength of 0.77954 m. if the speed of sound is 343.00 m/s, what pitch is this note?

9. an f note has a frequency of 698.46 hz. calculate its wavelength in meters.

10. a b note has a frequency of 493.88 hz. calculate its wavelength in meters.

1:A

2:E

3:C

4:0.5840

5:0.6945

6:0.4911

7:D

8:G

9:0.4375

10:0.5203

#1) 0.77955f = 343

Divide both sides by 0.77955:

0.77955f/0.77955 = 343/0.77955

f = 439.997 ≈ 440. This is for A.

#2) 0.52028f = 343

Divide both sides by 0.52028, and you get f = 659.260.  This is for E.

#3) 0.65552f = 343

Divide both sides by 0.65552, and you get f = 523.25.   This is for C.

#4) 587.33λ = 343

Divide both sides by 587.33 and you get λ = 0.583999 ≈ 0.5840.

#5) 493.88λ = 343

Divide both sides by 493.88, and we get λ = 0.6945.

#6) 698.46λ = 343

Divide both sides by 698.46 and you get λ = 0.49108 ≈ 0.4911.

#7) 0.5840f = 343

Divide both sides by 0.5840 and you get f = 587.3288 ≈ 587.33.  This is for D.

#8) 0.4375f = 343

Divide both sides by 0.4375 and you get f = 784. which is G.

#9) 783.99λ = 343

Divide both sides by 783.99 and you get λ = 0.4375.

#10) 659.26λ = 343

Divide both sides by 659.26 and you get λ = 0.52028 ≈ 0.5203.

hope this helped <3

it should be all of them because it asks if you included all of those in your answer

explanation:

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%