Sodium hydrogen carbonate nahco3 , also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid hcl , which the stomach secretes to digest food. drinking a glass of water containing dissolved nahco3 neutralizes excess hcl through this reaction: hcl (aq) + nahco3 (aq) → nacl (aq) + h2o (l) + co2 (g) the co2 gas produced is what makes you burp after drinking the solution. suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 200.ml of a 0.035 m hcl solution. what mass of nahco3 would he need to ingest to neutralize this much hcl ? be sure your answer has the correct number of significant digits.

The mass of NaHCO₃ that the man would need to ingest to neutralize this much HCl is 0.059 g.

Explanation:

1) Chemical equation (given):

Both sides have the same number of atoms of each element:

Element       Let side      Right side

H                  1 + 1 = 2       1 × 2 = 2

Cl                 1                   1

Na                1                   1

C                  1                   1

O                 3                   1 + 2 = 3

Hence, the equation is balanced.

2. Mole ratios:

2) Determine the number of moles of HCl in solution:

3) Set a proportion with the stoichiometric ratio and the actual ratio:

        ⇒ x = 0.00070 mol NaHCO₃

4. Convert 0.0070 mol NaHCO₃ to grams:

The answer has two significant digits because the molarity (0.035 M) is reported with two signficant digits.

lithosphere and asthenosphere

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j