Acylinder with a moveable piston contains 0.87 mol of gas and has a volume of 334 ml. what will its volume be in an additional 0.22 mol of gas is added to the cylinder?

418.46 ml.

Explanation:

V = n x constant.

∴ V₁n₂ = V₂n₁

V₁ = 334 ml, n₁ = 0.87 mol, V₂ = ??? ml, n₂ = (0.22 + 0.87) = 1.09 mol.

∴ V₂ = (V₁n₂) / n₁ = (334 ml)(1.09 mol) / (0.87 mol) = 418.46 ml.

2b2t

explanation:

2b2t

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