The mass of a single gold atom is 3.27×10-22 grams. how many gold atoms would there be in 70.6 milligrams of gold?

 [Total mass of gold atoms] = [Mass of one gold atom] x [number of gold atoms]  

divide both sides by mass of one atom:  

[Total mass of gold atoms] / [Mass of one gold atom] = [number of gold atoms]  

(0.130 grams) / (3.27E-22 grams/atom) = 3.975535168E20 or 397 quintillion gold atoms.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)