Aluminum has valence electrons. the easiest way for al to acquire a full outer shell is to __ __ electrons, forming an ion with a charge

This element has 3 valance electrons and it will loose electrons to form a ion.

Explanation:

Aluminium is the 13th element in our periodic table.

The valance shell electronic configuration of this element is:

As, there are 3 electrons in the outermost shell, Therefore, total number of valence electrons of this element are 3.

For this element loosing 3 electrons will be easy than to gain 5 electrons to acquire a full outer most shell configuration. Therefore, this element will loose 3 electrons.

When this element looses 3 electrons, it looses negative charge and starts to form positive ion. And it form an ion having +3 charge.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j