What is the velocity of 1.4 moles of bromine in a 3.5 l container at 4.35 atm?

Explanation:

Let the temperature at which gas is moving be T

Pressure exerted by the gas , P = 4.35 atm

Volume occupied by the gas ,V = 3.5 l

Moles of  bromine gas,n = 1.4 moles

Consider the bromine gas is behaving ideal .

Mass of bromine gas,M = Moles × Molar mass = 1.4 mole × 160 g/mol = 224 g = 0.224 kg

Value of R = 8.314 J/mol K

Root mean square velocity of the bromine gas:

Average velocity of the bromine gas:

Most probable velocity:

the answer is the first option

explanation:

just googled it m8. not that hard

lol

16

explanation:

the marks go by 4s