Agas has a volume of 27.5 l at 302 k and 1.40 atm. how many moles are in the sample of gas?

1.55 mol  

Step-by-step explanation:

We can use the Ideal Gas Law to solve this problem.

pV = nRT     Divide both sides by RT

 n = (pV)/(RT)

Data:

p = 1.40 atm

V = 27.5 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 302 K

Calculations:

n = (1.40 × 27.5)/(0.082 06 × 302)

  = 1.55 mol

c. 75.7

i think that is the right

points

explanation: