If 22.5 liters of oxygen reacted with excess of hydrogen, how many liters of water vapor could be produced?

45 L

Explanation:

Assuming normal temperature and pressure (NTP) and ideal gas behaviour, 22.5 L are equivalent to:

PV = nRT

n = PV/RT

n = (1*22.5)/(0.082*273.15)

n = 1 mol

Oxygen and hydrogen react to form water as  follows:

2 H2 (g) + O2 (g) -> 2 H2O (g)

From the balanced equation, we know that 1 mol of Oxygen produces 2 moles of water. The volume occupied by these 2 moles is:

PV = nRT

V = nRT/P

V =  2*0.082*273.15/1

V = 45 L

Know we can see the assumption of NTP conditions was unnecessary, the ratio between moles of oxygen consumed and moles of water produced is 1:2, so the ratio between volumes.

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.