These questions are based on the attached photo. the experiment is about burning magnesium metal with oxygen. 1. write the balanced chemical equation for the reaction you are performing. 2. calculate the mass of magnesium metal used in each trial. o trial 1: o trial 2: 3. calculate the actual yield of magnesium oxide for each trial. o trial 1: o trial 2: 4. magnesium is the limiting reactant in this experiment. calculate the theoretical yield of mgo for each trial. o trial 1: o trial 2: 5. determine the percent yield of mgo for your experiment for each trial. o trial 1: o trial 2: 6. determine the average percent yield of mgo for the two trials. your company currently uses a process with a similar cost of materials that has an average percent yield of 91 percent. if the average percent yield of this process is higher than that, this could save the company money. what is your recommendation to the company? support your recommendation using your data, calculations, and understanding of stoichiometry gathered from this lab.

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Write the balanced chemical equation for the reaction you are performing.

2Mg+ O2 → 2MgO

2.​Calculate the mass of magnesium metal used in each trial.

o Trial 1: 26.945-26.691

Mg metal= 0.254 g

o Trial 2: 26.948-26.691

Mg metal= 0.257 g

3.​Calculate the actual yield of magnesium oxide for each trial.

o Trial 1: 27.108-26.691

MgO= 0.417 g

o Trial 2: 27.110-26.691

MgO= 0.419 g

4.​Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.

o Trial 1: 0.254g*1 mol/24.305g Mg*2mol MgO/2mol Mg*40.305/1g MgO

0.421g MgO

o Trial 2: 0.257g*1 mol/24.305g Mg*2mol MgO/2mol Mg*40.305/1g MgO

0.426g MgO

5.​Determine the percent yield of MgO for your experiment for each trial.

o Trial 1: 0.417/0.421*100= 99.1%

o Trial 2: 0.419/0.426*100= 98.4%

6.​Determine the average percent yield of MgO for the two trials.

99.1+98.4= 98.8%

Questions and Conclusions:

1. Describe the process that was used in this lab to create magnesium oxide, specifically identifying the type of chemical reaction. Explain why the product had a higher mass than the reactant, and how this relates to conservation of matter.

Mg was heated with O2 to produce MgO. The reaction used to create magnesium oxide was oxidation reaction. It was an oxidation reaction because Mg loss electrons to react with O, magnesium gained O and oxidized to MgO. The product had a higher mass than the reactant because the reactant bonded to O and formed MgO, so the product had a higher mass due to the gain of O atom over the reactant Mg. This relates to conservation of matter, because the mass of products must be the same as the mass of reactants.

2. What sources of error may have contributed to the percent yield not being 100 percent? Think about things that may have led to inaccurate measurements or where the mass of the product could have been lost if this experiment was conducted in a physical laboratory.

Temperature of the Bunsen burner, Magnesium scraped off by steel wool.

3. When conducting this experiment, some procedures call for heating the substance several times and recording the mass after each heating, continuing until the mass values are constant. Explain the purpose of this process and how it might reduce errors.

It might reduce errors by keeping track of all the measurements of weight

passed in september 1935, these laws are known as nuremberg laws.   they forbid jews from marrying but not directly forced them to divorce aryans. what is most noticeable is the fact that the jews were defranchised, meaning by this that they were not expected to have any civil rights, including the right to vote. the right answer is deprived of the right to vote.