What is the percent composition of ca(oh)2

The percentage composition of CA(OH)2 is as follows;

54.05% Ca.43.24% O2.70% H

The percentage composition of Ca(OH)2 can be obtained by first determining the molar mass of Ca(OH)2 as follows;

Ca = 40O = 16H = 1

In essence, the molar mass of Ca(OH)2 is;

Ca(OH)2 = 40 + (16+1) × 2Ca(OH)2 = 74

Therefore;

% Ca = 40/74 × 100% = 54.05%% O = 32/74 × 100% = 43.24%% Ca = 2/74 × 100% = 2.70%

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% of Ca = 54.092 %.

% of O = 43.188 %.

% of H = 2.721 %.

Explanation:

The molar mass of Ca(OH)₂ = Atomic mass of Ca + (2 x atomic mass of O) + (2 x atomic mass of H) = 40.078 + (2 x 15.999) + (2 x 1.00798) = 74.09268 g/mol.To calculate the % composition of each element:For Ca:

% of Ca = (Atomic mass of Ca / Molar mass of Ca(OH)₂) x 100 = (40.078 / 74.09268) x 100 = 54.092 %.

For O:

% of O = (2 x atomic mass of O / molar mass of Ca(OH)₂) x 100 = (2 x 15.999 / 74.09268) x 100 = 43.188 %.

For H:

% of H = (2 x atomic mass of H / molar mass of Ca(OH)₂) x 100 = (2 x 1.00798 / 74.09268) x 100 = 2.721 %.

Ithink it’s 3 as the answer.

Mgo2 is the oxidation state of manganese oxide