It takes moles of oxygen to burn 32.0 g of methane. ch4 + 2o2 → co2 + 2h2o a. 1 mol b. 4 mol c. 3 mol d. 2 mol

the balanced equation for the combustion reaction is

CH₄ + 2O₂ ---> CO₂ + 2H₂O

molar ratio of methane - CH₄ to O₂ is 1:2

mass of methane burned - 32.0 g

number of methane moles burned - 32.0 g / 16 g/mol = 2 mol

according to molar ratio 1 mol of methane reacts with 2 mol of oxygen

therefore 2 mol of methane reacts with 4 mol of oxygen

answer is B. 4 mol

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

1 a

2 d

3 a

4 c

explanation: