Chemistry, 25.06.2019 14:00 harleyandpope90
Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.
Answers: 1
![[\text{H}^{+}] = 10^{-\text{pH}}](/tpl/images/0015/8660/d14eb.png)
, where ![[\text{H}^{+}]](/tpl/images/0015/8660/3f662.png)
is the concentration of proton in the solution.
.![[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w](/tpl/images/0015/8660/76721.png)
, where ![[\text{OH}^{-}]](/tpl/images/0015/8660/3da65.png)
the concentration of hydroxide ions and 
is the dissociation constant of water.
at 0.10 MPa and 25 °C. As a result, ![[\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}](/tpl/images/0015/8660/0d14c.png)
. 
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Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hyd...
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