Jack has 100 milliliters of a 12 molar solution of sulfuric acid. how much of it should he put into a graduated cylinder to make 20 milliliters of a 1.2 molar solution? i'm studying for asvab can someone walk me through the solution

This is a dilution equation where a certain volume from a more concentrated solution is diluted with distilled water to make a less concentrated solution. We can use the dilution equation as follows

c1v1 = c2v2

where c1 is concentration and v1 is volume of the more concentrated solution

and c2 is concentration and v2 is volume of the diluted solution to be prepared

where c1 - 12 M

c2 - 1.2 M

v2 - 20 mL

we need to find v1 , that is the volume that should be taken from the 12 M solution to make 20 mL of 1.2 M solution

substituting these values in the equation

12 M x v1 = 1.2 M x 20 mL

v1 = 2 mL

therefore 2 mL of 12 M solution should be taken to the graduated cylinder and diluted up to 20 mL to make a 1.2 M solution

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2