What would be the temperature change 3.0 g of water absorbed 15 j of heat

The change in temperature of the sample has been .

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The expression for specific heat has been given as:

For the given water sample,

The mass of sample has been

The heat absorbed by the sample has been

The specific heat of water has been

Substituting the values for change in temperature, :

The change in temperature of the sample has been .

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1.2 °C  

Step-by-step explanation:

The formula relating the heat (q) absorbed by an object, the mass (m), and the temperature change (ΔT) is

  q = mCΔT     Divide both sides by mC  

ΔT = q/(mC)

Data:

q  = 15 J

m = 3.0 g

C  = 4.184 J·°C⁻¹g⁻¹

Calculation:

ΔT = 15/(3.0 × 4.184)

ΔT = 15/12.6

ΔT = 1.2 °C