Given 16.2 grams of substance y, if the substance absorbs 2722 joules of energy and the specific heat of the substance is 9.22 j/g·°c, what is the final temperature of the substance if the initial was 26 degrees celsius?

Since the substance absorbs heat, it is expected that the temperature will rise. The formula for the internal energy of a substance is given by the equation:

ΔU = mCpΔT

where:

ΔU = internal energy
m = mass of substance
Cp = specific heat capacity of substance
ΔT = change in temperature

ΔU = 2722 Joules = 16.2 grams (9.22 J/g-°C) (Tf - 26°C)

This gives a final temperature of Tf = 44.22 °C

Cis the