How many atoms of n are in 137.0 grams of n2o3?

The number of N atoms in 137.0 g of N2O3 21.67 x 10∧23 atoms.

Explanation:

We must obtain the number of moles of the compound: (n = mass/molar mass), mass = 137.0 g and molar mass of N2O3 = 76.01 g/mol.n = (137.0 g)/ (76.01 g/mol) = 1.80 mol.It is necessary to determine the number of molecules of this sample.Every mole contains Avagadro's number (6.02 x 10^23) of molecules.The number of molecules = (6.02 x 10^23)(1.80) = 10.84 x 10∧23 molecules.Every molecule of N2O3 contain 2 atoms of N.The number of N atoms in 137.0 g of N2O3 = (10.84 x 10∧23 molecule) (2 atoms) = 21.67 x 10∧23 atoms.